2cos^2x+sinx=2

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Solution for 2cos^2x+sinx=2 equation:


Simplifying
2cos2x + sinx = 2

Solving
2cos2x + insx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1insx' to each side of the equation.
2cos2x + insx + -1insx = 2 + -1insx

Combine like terms: insx + -1insx = 0
2cos2x + 0 = 2 + -1insx
2cos2x = 2 + -1insx

Divide each side by '2os2x'.
c = o-1s-2x-1 + -0.5ino-1s-1

Simplifying
c = o-1s-2x-1 + -0.5ino-1s-1

Reorder the terms:
c = -0.5ino-1s-1 + o-1s-2x-1

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